How to solve this one?

Consider the Archimedian Spiral r = 40 + 3, 0 E [0, 27] plotted below in black. The tangent to the spiral when 0 = 7 is plotted in blue. 3 x 4 8 7 5 TE 3 TC 2 A parametric form of this spiral can be found by using t = 0 as the parameter: a(t) = [(3 + 4t) cos(t), (3 + 4t) sin(t) ] . Find the point a(7) = [-3-4*Pi,0] The Cartesian equation of the tangent to the curve at a(7 ) is y = The Cartesian equation of the normal to the curve at a (7 ) is y = Note: the Maple syntax for [7, 0] is [Pi , 0] and you may find concepts from the previous Week 9 topic useful here