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http://college.cengage.com/mathematics/blackboard/shared/content/video_explanations/video_wrapper.html?filename=v01090a http://college.cengage.com/mathematics/blackboard/shared/content/video_explanations/video_wrapper.html?filename=v01090b http://college.cengage.com/mathematics/blackboard/shared/content/video_explanations/video_wrapper.html?filename=v02262a Think of an application where you can use hypothesis testing to test a premises. Use .05 for your alpha and give the

http://college.cengage.com/mathematics/blackboard/shared/content/video_explanations/video_wrapper.html?filename=v01090a

http://college.cengage.com/mathematics/blackboard/shared/content/video_explanations/video_wrapper.html?filename=v01090b

http://college.cengage.com/mathematics/blackboard/shared/content/video_explanations/video_wrapper.html?filename=v02262a

Think of an application where you can use hypothesis testing to test a premises. Use .05 for your alpha and give the scenario. Set up the problem, solve it and state your conclusions. See the example below.Then respond to at least 2 classmates.

First post: First summarize the 3 videos and make a note of what you learned. Then create your own hypothesis test.For instance, XYZ car company boast that it's new car Eco Auto gets at least 59 miles to the gallon. Given a sample mean of 57 and a standard deviation of 3.5 where 35 people were tested, find the z value and p score. Hint: Use the P value calculator in the announcements to find the p score. Note: On this one you do not need to attach an excel spreadsheet.

Student Response:

Ho: u>=59

Ha: u<59

You can put this in excel or your calculator

= (59-57)/(3.5/35^.5)

=3.38

or enter this in excel

=norm.dist(59,57,3.5/35^.5,true)

and hit enter

Then take that value which we will call A

and type this in excel

=norm.s.inv(A)

and hit enter

Using the z to p value calculator with a=.05, 1 tailed test and z=3.38, you get

p=.000362

Since p < .05, you reject the null

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