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https://www.chegg.com/homework-help/questions-and-answers/class-workoutclass-workout-class-offered-gym-private-attributes-name-name-workoutclass-req-q44040301 For this question, I need implementation for the following functions. def register(self, time_point: datetime, client: str, workout_name: str) -> bool: Add to the

https://www.chegg.com/homework-help/questions-and-answers/class-workoutclass-workout-class-offered-gym-private-attributes-name-name-workoutclass-req-q44040301

For this question, I need implementation for the following functions.

def register(self, time_point: datetime, client: str, workout_name: str) \ -> bool: """Add to the WorkoutClass with that is being offered at iff the client has not already been registered in any course (including ) at , and the room is not full.

If the WorkoutClass is being offered in more than one room at , then add the client to the room that has the most clients already registered but still has available space. In the case of a tie, register in any of the tied classes.

Return True iff the client was added.

Precondition: the WorkoutClass with is being offered in at least one room at .

>>> ac = Gym('Athletic Centre') >>> diane = Instructor(1, 'Diane') >>> diane.add_certificate('Cardio 1') True >>> ac.add_instructor(diane) True >>> ac.add_room('Dance Studio', 50) True >>> boot_camp = WorkoutClass('Boot Camp', ['Cardio 1']) >>> ac.add_workout_class(boot_camp) True >>> sep_9_2022_12_00 = datetime(2022, 9, 9, 12, 0) >>> ac.schedule_workout_class(sep_9_2022_12_00, 'Dance Studio',\ boot_camp.name, diane.get_id()) True >>> ac.register(sep_9_2022_12_00, 'Philip', 'Boot Camp') True >>> ac.register(sep_9_2022_12_00, 'Philip', 'Boot Camp') False """

def offerings_at(self, time_point: datetime) -> list[dict[str, str | int]]: """Return a list of dictionaries, each representing a workout offered at this Gym at .

The offerings should be sorted by room name, in alphabetical ascending order.

Each dictionary must have the following keys and values: 'Date': the weekday and date of the class as a string, in the format 'Weekday, year-month-day' (e.g., 'Monday, 2022-11-07') 'Time': the time of the class, in the format 'HH:MM' where HH uses 24-hour time (e.g., '15:00') 'Class': the name of the class 'Room': the name of the room 'Registered': the number of people already registered for the class 'Available': the number of spots still available in the class 'Instructor': the name of the instructor If there are multiple instructors with the same name, the name should be followed by the instructor ID in parentheses e.g., "Diane (1)"

If there are no offerings at , return an empty list.

NOTE: - You MUST use the helper function create_offering_dict from gym_utilities to create the dictionaries, in order to make sure you match the format specified above. - You MUST use the helper method _is_instructor_name_unique when deciding how to format the instructor name.

>>> ac = Gym('Athletic Centre') >>> diane1 = Instructor(1, 'Diane') >>> diane1.add_certificate('Cardio 1') True >>> diane2 = Instructor(2, 'Diane') >>> david = Instructor(3, 'David') >>> david.add_certificate('Strength Training') True >>> ac.add_instructor(diane1) True >>> ac.add_instructor(diane2) True >>> ac.add_instructor(david) True >>> ac.add_room('Dance Studio', 50) True >>> ac.add_room('Room A', 20) True >>> boot_camp = WorkoutClass('Boot Camp', ['Cardio 1']) >>> ac.add_workout_class(boot_camp) True >>> kickboxing = WorkoutClass('KickBoxing', ['Strength Training']) >>> ac.add_workout_class(kickboxing) True >>> t1 = datetime(2022, 9, 9, 12, 0) >>> ac.schedule_workout_class(t1, 'Dance Studio', boot_camp.name, 1) True >>> ac.schedule_workout_class(t1, 'Room A', kickboxing.name, 3) True >>> ac.offerings_at(t1) == [ ... { 'Date': 'Friday, 2022-09-09', 'Time': '12:00', ... 'Class': 'Boot Camp', 'Room': 'Dance Studio', 'Registered': 0, ... 'Available': 50, 'Instructor': 'Diane (1)' }, ... { 'Date': 'Friday, 2022-09-09', 'Time': '12:00', ... 'Class': 'KickBoxing', 'Room': 'Room A', 'Registered': 0, ... 'Available': 20, 'Instructor': 'David' } ... ] True """

def to_schedule_list(self, week: datetime = None) \ -> list[dict[str, str | int]]: """Return a list of dictionaries for the Gym's entire schedule, with each dictionary representing a workout offered (in the format specified by the docstring for offerings_at).

The dictionaries should be in the list in ascending order by their date and time (not the string representation of the date and time). Offerings occurring at exactly the same date and time should be in alphabetical order based on their room names.

If is specified, only return the events that occur between the date interval (between a Monday 0:00 and Sunday 23:59) that contains .

Hint: The helper function can be used to determine if one datetime object is in the same week as another.

>>> ac = Gym('Athletic Centre') >>> diane1 = Instructor(1, 'Diane') >>> diane1.add_certificate('Cardio 1') True >>> diane2 = Instructor(2, 'Diane') >>> david = Instructor(3, 'David') >>> david.add_certificate('Strength Training') True >>> ac.add_instructor(diane1) True >>> ac.add_instructor(diane2) True >>> ac.add_instructor(david) True >>> ac.add_room('Studio 1', 20) True >>> boot_camp = WorkoutClass('Boot Camp', ['Cardio 1']) >>> ac.add_workout_class(boot_camp) True >>> kickboxing = WorkoutClass('KickBoxing', ['Strength Training']) >>> ac.add_workout_class(kickboxing) True >>> t1 = datetime(2022, 9, 9, 12, 0) >>> ac.schedule_workout_class(t1, 'Studio 1', boot_camp.name, 1) True >>> t2 = datetime(2022, 9, 8, 13, 0) >>> ac.schedule_workout_class(t2, 'Studio 1', kickboxing.name, 3) True >>> ac.to_schedule_list() == [ ... { 'Date': 'Thursday, 2022-09-08', 'Time': '13:00', ... 'Class': 'KickBoxing', 'Room': 'Studio 1', 'Registered': 0, ... 'Available': 20, 'Instructor': 'David' }, ... { 'Date': 'Friday, 2022-09-09', 'Time': '12:00', ... 'Class': 'Boot Camp', 'Room': 'Studio 1', 'Registered': 0, ... 'Available': 20, 'Instructor': 'Diane (1)' }, ... ] True """

def __eq__(self, other: Any) -> bool: """Return True iff this Gym is equal to .

Two gyms are considered equal if they have name the same name, instructors, workouts, room capacities, and schedule.

>>> ac = Gym('Athletic Centre') >>> ac2 = Gym('Athletic Centre') >>> ac == ac2 True """

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