Hugo averages 78 words per minute on a typing test with a standard deviation of 12 words per minute. Suppose Hugo's words per minute on a typing test are normally distributed. Let X= the number of words per minute on a typing test. Then, XN(78,12). Suppose Hugo types 58 words per minute in a typing test on Wednesday. The z-score when x=58 is ________. This z-score tells you that x=58 is ________ standard deviations to the ________ (right/left) of the mean, ________. Correctly fill in the blanks in the statement above.

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Suppose Hugo types 58 words per minute in a typing test on Wednesday. The z-score when x=58 is 1.667. This z-score tells you that x=58 is 1.667 standard deviations to theleftof the mean, 78.

Suppose Hugo types 58 words per minute in a typing test on Wednesday. The z-score when x=58 is 1.667. This z-score tells you that x=58 is 1.667 standard deviations to therightof the mean, 78.

Suppose Hugo types 58 words per minute in a typing test on Wednesday. The z-score when x=58 is 1.333. This z-score tells you that x=58 is 1.333 standard deviations to therightof the mean, 78.

Suppose Hugo types 58 words per minute in a typing test on Wednesday. The z-score when x=58 is 1.333. This z-score tells you that x=58 is 1.333 standard deviations to theleftof the mean, 78.