HW 1 1.1,1 1.2 Score: 0f29 Of'l'? answered 0 Question 16 v Day Customers Monday 70 Tuesday Wednesday Thursday Friday Saturday Sunday 78 88 82 71 65 88 The table shows a recent random samp.e of customers at a cafe. At a 1096 Level of Significance, test to see if customers are distributed uniformly throughout the week. 1. The hypotheses are : '31:? Ho:Customers are distributed uniformly through the week Ha:Customers are not distributed uniformly through the week {:33 Ho:Customers are not distributed uniformly through the week Ha:Customers are distributed uniformly through the week 2. This is a '33:? right'i:3' two' left tailed test; d.f. = 3a. The STS [to 2 decimals] is x2 = 3b. The P-value {to 3 decimals} = 4a. The decision at a = 10% is '33:} Reject Ho '33:} Do not reject Ho 4b. The conclusion is '33:? There is insufficient evidence to conclude that customers are not distributed uniformly through the week '33:? There is insufficient evidence to conclude that customers are distributed uniformly through the week '33:} There is sufficient evidence to conclude that customers are not distributed uniformly through the week 0 There is sufficient evidence to conclude that customers are distributed uniformly through the week 0 Question 17 v 1" "rug no no]; 45.J 51".5 .175 63o" 69.3? F5.) 8f.5 8173? Exam Scores Range Frequency Below 57.5 5 57.5-63.5 31 63.5-69.5 61 69.5-75.5 74 75.5-81.5 26 Above 81.5 3 The graph and table above show results from the same random sample of 200 exam scores. At a 1% Level of SignificanceJ test to see if the data fits a normal distribution with mean ,u = 59.5 and standard deviation 0:5. To figure out the E column, use the Empirical Rule: {68% within one standard deviation, 95% within two standard deviations,the rest beyond two standard deviations. Note: Even if you get E