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HWOB: Problem 2 (1 point) We consider the non-homogeneous problem 1! 23f 8y 2 1441227 First we consider the homogeneous problem 1.! 230' 39' =

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HWOB: Problem 2 (1 point) We consider the non-homogeneous problem 1!" 23f 8y 2 1441227 First we consider the homogeneous problem 1.!\" 230' 39' = I]: 1) the auxiliary equation is or2 + bi\" + c = = 0. 2) The roots of the auxiliary equation are (enter answers as a comma separated list). 3) A fundamental set of solutions is (enter answers as a comma separated list). Using these we obtain the the complementary solution ye = clyl + City; for arbitrary constants c1 and c2. Next we seek a particular solution 1;? of the nonhomogeneous problem 1;\" 23f 3y = 1448'\" using the method of undetermined coetcients [See the link beiow for a help sheet) 4) Apply the method of undetermined coefcients to nd 3,, = We then nd the general solution as a sum ofthe complementary solution ya = clyl + cap; and a particular solution: 1; = ye + 3,5,. Finaliy you are asked to use the general solution to solve an NP. 5) Given the initial conditions gm) = 2 and 16(0) = 22 nd the unique solution to the IVP y

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