I am having difficulty with the last section of this problem. Could you share the function I should use and offer guidance on how to solve?

According to survey data, the distribution of arm spans for females is approximately Normal with a mean of 65.6 inches and a standard deviation of 3.3 inches. a. What percentage of women have arm spans less than 61 inches? b. A particularfemale swimmer has an estimated arm span of 73 inches. What percentage of females have an arm span at least as long as this person? a. The percentage of women with arms spans less than 61 inches is 8.2 %. (Round to one decimal place as needed.) b. The z-score for an arm span of 73 inches is 2.24 . (Round to two decimal places as needed.) The percentage of females who have an arm span at least as long is this person is %. (Round to one decimal place as needed.)