I am stuck again, Could someone show me how they got the P-value from this Chi Square Test?

*Note: If you could show step-by-step equations so I can follow would be nice. Also, if you know how to do it in excel using a formula, that would help as well.

Thank you in advance.

A recent study examined the effects of carbon monoxide exposure on a group of construction workers. The following table presents the numbers of workers who reported various symptoms, along with the shift (morning, evening, or night) that they worked. Morning Shift Evening Shift Night Shift Influenza 14 19 15 Headache 25 22 Weakness 18 11 Shortness of Breath 4 10 Send data to Excel Test the hypothesis of independence. Use the a =0.01 level of significance and the P-value method with the TI-84 Plus calculator. What do you conclude? Part 1 of 4 State the null and alternate hypotheses. Ho: The shift and reported symptoms |are independent. H1: The shift and reported symptoms are not independent. This hypothesis test is a right-tailed test. Part 2 of 4 X Find the P-value. Round your answer to four decimal places. The P-value is 16.8119 . Correct Answer: 0.0078