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i am using python - Logistic difference equation Last assignment, we also introduced the logistic difference equation: N.+1 = N exp(r(1 - N.)) In the
i am using python - Logistic difference equation Last assignment, we also introduced the logistic difference equation: N.+1 = N exp(r(1 - N.)) In the code cell below, iterate this equation for four different values of the growth rater: values of t from t = 0 to Imax = 30 . No = [0.1, 0.1, 0.1, 0.075) i.e. depends on value ofr . r=[1.8, 2.3, 2.6, 3.3) Similar to above, use a different subplot for each value ofr. Your results should look very similar to those published in figure 1 of May (1974). Note that we have chosen a carrying capacity K = 1 so it does not appear in our equation. In particular you should see the following: (a)r 1.8, stable equilibrium point; (b) r = 2.3, stable 2-point cycle; (c)r. 2.6, stable 4-point cycle; (d to f) in the chaotic regime, where the details of the solution depends on the initial population value, (d) r.3.3 (No = 0.075). Note that May (1974) had additional panels with (e) r = 3.3 with No 1.5, and (t) r=5.0 with No-0.02. 11 02: YOUR CODE HERE import numpy as np import matplotlib.pyplot as pit re/1.8,2.3,2.6,3.3
i am using python
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