I (c) A farm brings 15 tons of watermelon to market. Find a 90% condence interval for the population mean cash value of this crop. What is the margin of error? Hint: 1 tan is 2000 pounds. First, note that the sample mean is in units of dollars per 100 pounds of watermelon. We must convert 15 tons to pounds before finding the confidence interval. 15 tons x M = 30,000 lbs 1 ton From part (a), we know that the confidence interval for 100 pounds of watermelon is $6.38 to $7.38. Starting with the lower value, convert this interval to be in terms of 30,000 pounds. (Round your final answer to the nearest cent.) $6.38 x 100 lbs ' 30,000 lbs (Elm 15:\" Do the same calculation for the upper value. (Round your final answer to the nearest cent.) $7.38 x 100 lbs ' 30,000 lbs (l:l)7-38:x $:=x || ><