I cant seem to know how to solve this two problems, help needed!

Using the prior solution find the equation of the tangent line to the curve below when x = 0 and y > 0. 4. (2-6)2 4( y-1)2 48 16 = 1, (3 points) 5. Also find the equation of the normal line to the curve at the same point. (2 points)