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i. Consider the following function: int answer; if(n>0) { answer -(mystery(n-2) +3* mystery(n/2) +5); retum answer else return 1 Winte down the complete recurence relation,

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i. Consider the following function: int answer; if(n>0) { answer -(mystery(n-2) +3* mystery(n/2) +5); retum answer else return 1 Winte down the complete recurence relation, Tm), for the running time of mystery(n). Be sure you include a base case T(0). You do not have to e o actually solve this relation, just write it down

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