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I do t understand this Given the function 9(33) : 4:133 | 36:132 | 96:13, find the first derivative, g'(:r;). M =l: Notice that g'(:c)

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I do t understand this

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Given the function 9(33) : 4:133 | 36:132 | 96:13, find the first derivative, g'(:r;). M =l: Notice that g'(:c) = 0 when a: = 4, that is, g'(4) = 0. Now, we want to know whether there is a local minimum or local maximum at a: = 4, so we will use the second derivative test. Find the second derivative, g\"(:L'). W) =: Evaluate g\"(4). 9"(4) = Based on the sign of this number, does this mean the graph of 9(m) is we or W at a: = 4? At :13 = 4 the graph 0fg(:13) is Select an answer 0 Based on the concavity of 9(53) at a: = 4, does this mean that there is a local minimum or local maximum at m = 4? At :13 : 4 there is a local Select an answer 0

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