I = FAngt Let's revisit our bouncing basketball. We broke the question up into three parts. Remember for this scenario, the direction downwards will be considered the negative direction. First, the ball leaves the student's hands with a downwards initial velocity. The ball has a mass of 0.60 kg and an initial velocity of 1.1 m/s down. After the ball falls about 0.50 meters, it has a velocity of 3.3 m/s towards the ground. We know the average force on the ball after it left the student's hand is the same as the force of gravity, or 5.9 N. Using impulse, how much time (in s) does it take for the ball to reach 3.3 m/s7 0 as x x incorrect. Remember you should set the change in momentum of the ball equal to the product of the time and average force on the ball. s \\ 7' As we solved earlier, the ball experiences an impulse of 4.00 kg - m/s upward as it hits the ground. [fit takes 0.015 seconds for the ball to experience an impulse from the force on the ground, what is the average force (in N) on the ball from the ground? 26567 e; ./ Great, you correctly divided the impulse by the amount of time to determine the average force on the ball. N Now, let's imagine the basketball is low on air, causing it to bounce slightly differently. The mass is 0.50 kg and its initial velocity before it hits the ground is still 3.3 m/s down. However, it is now in contact with the ground for 0.025 seconds when it experiences an impulse of 4.0 kg . upward, What is the average force (in N) on the ball from the ground' s 16000 e; I Great, you correctly divided the impulse by the amount of time to determine the average force on the ball. N