i) Find the change of the bar's gravitational potential energy as it falls to 02 = 350. k = 61 N/m Vg.2 - VLI = ii) Find the change of the spring's potential energy as it falls to 02 = 35. 2.8 m Vsp,2 - Vsp.1 = iii) Write an equation relating the speed of the bar's center to its angular speed at 02 = 35. VOT v(w) = iv) Find the angular speed of the bar when it reaches 02 = 35. The 6.0 kg bar is released from rest at an angle of 01 = 250. The spring attached to the top of the (2 = bar was unstretched when the bar was vertical