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I found out that the mortality rate of the sample of patients in MS-DRG 291 is 9.7% which is statistically different than the US rate

I found out that the mortality rate of the sample of patients in MS-DRG 291 is 9.7% which is statistically different than the US rate of mortality which is 6.0% , i want to

  1. Test the hypothesis that the mortality rate for the hospital that generated the sample data is different from the US rate of 6.0%.? Below i am adding 5 steps on how to test the hypothesis with one sample z proportion and also adding the example 4.12 that shows how is needs to be done, please follow that and solve my answer.
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helachip A Practical Approach to Analyzing Healthcare Data 78 test are the test stations in a critical value based on aneira after tire distribution 4. ject the null bungewants it she calculated test statistic to there than the put la Propof Statistic son do not reject theportion to a standard fo mentin one sample, i for proportions. The formula for this test is P - Po Z -Jpox (1 - Po) in is the is the proportion value in the null hypothesis, is compared againgple prop from the the sample gorton value in the test statistic love of type I errast criticalofin homal distribution for the acceptable level of type 1 error to determile as the Hypothesis shomal distributionnot The normal andadd normal ames referney from the standard normal bell-shell curve becand be rejected (see figure 4.7). The startfront troffflat distribufiredi bell-shaped curve with a mean of zero and standard deviation of one. Figure 4.7 Standard normal distribution Standard Normal Distribution Function 0.45 0.4 0.35 0.3 0.25 Probability 0.2 0.13 O. 0.05 Z The critical values for common alpha levels may be found in table 4.5. A full standard norm distribution table may be found in many statistical texts or online. Table 4.5 Common standard normal distribution critical values Alpha level 0.1 Standard Normal Critical Value 0.05 1.282 0.025 0.01 1.645 0.005 1.960 2.326Analyzing Categorical Variables 79 tribution of the an the critical example 4.12 - One sample Z-test for proportions sample Z-test lose the gotor sammie rate for a company is 85 percent, An analyst collected supfiance ratesat table of 10 employees and determines that 7 received the vaces The sample sto coppermine if the company is meeting its compliance rate goal it Users are willing to accept a five percent chance of making the incorrect conclusion del the analyst will be using sample data to make a conclusion about the population of company proportion Silvees, this is an application of statistical inference. Specifically, the analyst can use the one itical values ample Z-test for proportions to determine if the sample supplies enough evidence to conclude etermine if allthe vaccine compliance rate is different from the goal. The hypothesis steps are listed below. 1. Determine the null and alternative hypotheses: referred to Null hypothesis (H.): p = 85 percent or 0.85 ution is a Alternative hypothesis (H.): p * 0.85 2. Set the acceptable type I error or alpha level The company leaders are willing to accept a five percent error rate. Alpha = 0.05 Select the appropriate test statistic Z is the appropriate test statistic 4. test statistic Compare the test statistic to a critical value based on alpha and the distribution of the Z = 0.70 - 0.85 -0.15 0.85 x (1 -0.85 ) 0. 11 = -1.36 10 5. Reject the null hypothesis if the calculated test statistic is more extreme than the critical value. If not, then do not reject the null hypothesis Since Ha is a two sided alternative (#) we select the critical value associated with the alpha level divided by two. We want to protect against both higher and lower alternatives. We reject H, if Z > 1.960 or Z Po or H: p zPo H : p

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help me resolving this please :)

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