Question
I got it to work! program accepts airport code and distance into a single linked list and tells you how far it is away from
I got it to work! program accepts airport code and distance into a single linked list and tells you how far it is away from the header, which happens to be LGA airport at distance 0. posting it on here for anybody that needs it. If any experts can clean up the code that would be awesome.
#include
using namespace std; struct Node { string code; double dist; Node* next; Node(string code1, double dist1,Node *next1=NULL) { code = code1; dist = dist1; next = next1; } }; //define class Airportlist { public: Node *head=NULL , *nexta, *data; public: Airportlist() {head = NULL;} void add(string realcode, double realnumber); void display(); void search(); }; //insertion void Airportlist::add(string realcode, double realnumber) {
if (head == NULL) { head = new Node(realcode, realnumber); } else { Node *nextloc = head; while (nextloc->next != NULL) nextloc = nextloc->next; nextloc->next= new Node(realcode, realnumber); }
}
//disp void Airportlist::display() { nexta = head; while (nexta->next) { cout << nexta->code << " " << nexta->dist <<" miles away from LGA " <
}
//main function int main() { int choice; Airportlist item; cout << "enter 1 to add airport, 2 to search, 3 to display list,4 to exit" << endl; cin >> choice; string dummycode; double dummydistance; while (choice!=4) { if (choice == 1) {
cout << "enter code for airport:" << endl; cin >> dummycode; cout << "enter distance:" << endl; cin >> dummydistance; item.add(dummycode, dummydistance); cout << endl;
} if (choice == 2) { item.display(); cout << endl; } if (choice == 3) { item.search(); cout << endl; } cout << "enter 1 to add airport, 2 display list, 3 to search list,4 to exit" << endl; cin >> choice; } return 0; }
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