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I have an algorithm and I trace two different data sets through it . The first input size is n = 1 0 0 while

I have an algorithm and I trace two different data sets through it. The first input size is n =100 while the second is of size n =10,000. It turns out both runs of the algorithm end up performing a constant number of comparisons to complete. What true statements can I make about the running time of this algorithm at this point (even if those statements do not represent a tight bound)? Select all that apply.
Question 3 options:
A)
The worst-case running time of the algorithm is O(2^n)
B)
The average-case running time of this algorithm is \Omega (1).
C)
The overall running time of the algorithm is \theta (1)
D)
The overall running time of this algorithm is \Theta (n).

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