I have completed my task of:

A.Provide the firstfiveterms of an arithmetic or geometric sequence that has a first term higher than 10 and a common difference or ratio that is positive but not 1.

1.Using the general formula for either the arithmetic or geometric sequence, derive the specificnthterm formula for the sequence from part A, showingallsteps.

2.Find the 30th term of the sequence from part A, using thenth term formula from part A1 and showingallwork.

B.Explain how to use patterns or sequences to determine the last digit of the number 7N, where N is the four-digit year of your birth.

Below is my submission. Do you think it was because I didn't say I was born in 1993?

This was my feedback: A repeating pattern of 7,9,3,1 is logically used to determine that the last digit of 7^1993 is 7. The first 4 powers of 7 are shown. This is not a sufficient number of powers to establish and validate this repeating pattern.

A} We will solve/provide the arithmetic sequence a1=20 and d (common difference) =10 S=o the first 5 terms will be 20, 20+10= 30,. 30+10=40, 40+10=50, 50+10=60 \"mm 1. Now we have the formula in arithmetic sequence An: A1+(n-1)d where AIn is nth term An: 20 + (n-1)x10 = 20 + 10n-10 = 10n+10 2. We have to find A30 An=10n+10 When n=30, A30: 30x10+10= 310 B) 71:7 72:49 73: 343 74: 2401 75 will have unit digit 7 hence 7" will repeat E unit digit after 4. 5:0 when we divide 1993 by 4, the remainder is 1. 5:0 the unit digit of 71993 will be same as unit digit 71. 5:0 the answer is 7