Question
I have completed the data table and the graphs, but I'm stuck on the calculations for the questions. Can anyone please help and explain the
I have completed the data table and the graphs, but I'm stuck on the calculations for the questions. Can anyone please help and explain the steps I should take? Thank you! Also the `y is being used in place of a y with a line over it to indicate the mean of y.
The data table located in the Lab Report Assistant shows data taken in a free-fall experiment.Measurements were made of the distance of fall (y) at each of the four precisely measured times. From this data, perform the following operations:
Time, t (s) | Dist. y (m) | Dist. y (m) | Dist. y (m) | Dist. y (m) | Dist. y (m) | ` y | ? | t^2 |
0 | 0 | 0 | 0 | 0 | 0 | - | 0 | 0 |
0.5 | 1 | 1.4 | 1.1 | 1.4 | 1.5 | 1.28 | 0.177012241 | 0.25 |
0.75 | 2.6 | 3.2 | 2.8 | 2.5 | 3.1 | 2.84 | 0.248997992 | 0.5625 |
1 | 4.8 | 4.4 | 5.1 | 4.7 | 4.8 | 4.76 | 0.224499443 | 1 |
1.25 | 8.2 | 7.9 | 7.5 | 8.1 | 7.4 | 7.82 | 0.318747549 | 1.5625 |
1. Complete the table.
2. Plot a graph `y versus t (plot t on the x-axis or abscissa).
3. Plot a graph `y versus t2 (plot t2 on the x-axis). The equation of motion for an object in free fall starting from rest is y = 1?2 gt2, where g is the acceleration due to gravity. This is the equation of a parabola, which has the general form y = ax2.
4. Determine the slope of the line and compute an experimental value of g from the slope value. Remember, the slope of this graph represents 1?2 g. (The equations I got from the spreadsheet by doing a polynomial trendline. For y vs t - y=4.9838x^2 - 0.041x. For y vs t^2 - y=0.1164x^2 + 4.7937x)
5. Compute the percent error of the experimental value of g determined from the graph in step 4. (Accepted value of g = 9.8 m/s2).
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