I have figured out the answers to questions 1 & 2, but need help with questions 3 & 4.

In Lab 6, you collected data from the iOLab device as it rolled down the ramp (while attached to a pulley), which was set to a known angle. Using this data, you made a plot of v2 vs. x, where x was the position along the ramp, and v2 was the velocity squared. Using conservation of mechanical energy, U + K = const. , it is possible to calculate what the l slope of this plot should be. Plugging in U = mgh and K = mv2 we can get, 2 2 1 mgh + am];2 2 const. > mg sin(6)x + Emv2 = const. > v2 2 2g sin(6)x + const. m where I have substituted h = sin(6 )x. The second term in the nal expression is just an intercept: since we only care about the slope of the graph, we can ignore it. (Please Note: the formula above does not account for the mass of the weight hanging over the pulley. This is because we will not be attaching the weight and pulley for the Lab Practical.) In Lab 6, we then used this as a way to measure g: we first we allowed the iOLab to roll down the ramp, then we exported the data that was collected, and made a graph of v2 (y-axis) vs. x (x- axis). The slope of this graph was measured, and the value was used to nd g by setting it equal to the predicted slope, and solving for g. For the second part of the lab practical, you will do this once again, for 6' = 15, only this time you will not attach a hanging mass to a string running over a pulley. Instead, you will just allow the iOLab device to roll down the ramp freely (which simplies the procedure). Once again, it is recommended you review the materials for Lab 6, to make sure you are familiar with the procedure, but remember: this time we will not be attaching the iOLab to a mass on a pulley. Questions: - A description of the setup you used, and the measurements you took, just as you would I'fyou were writing the procedure section of a lab report. 20 points - The graph you made of v2 vs. x from your exported iOLab data. 15 points - The measured value of 3 based on the slope of your graph. 10 points - Briey, explain whether or not you think your results agree well with the established value. 5 points V2 vs Position at 15 degrees 1.6 1.4 y = 2.3489x - 1.1874 R2 = 0.9985 1.2 1 v2 (m/s) 0.8 0.6 0.4 0.2 0 0 0.2 0.4 0.6 0.8 1 1.2 1.4 Time (s)