I have no idea about the c part of this question. Would you please help me with that?

Suppose the area that can be palnted uslng a slngle can of spray palnt Is slightly variable and follows a nearly normal dlstrlbutlon with a mean of 29 square feet and a standard devlatlon of 3 square feet. (a) What is the probability that the area covered by a can of spray paint is more than 31 square feet? (Round your answer to four decimal places.) 0.2514 (b) Suppose you want to spray paint an area of 465 square feet uslng 15 cans of spray paint. On average, how many square feet must each can be able to cover to spray palnt all 465 square feet? (Enter your answer as a whole number.) 31 (c) What is the probability that you can cover a 465 square feet area using 15 cans of spray paint? (Round your answer to four decimal places.) 0.9951 x (d) If the area covered by a can of spray palnt had a slightly skewed dlstrlbutlon, could you still calculate the probabllltles In parts (a) and (c) uslng the normal dlstrlbutlon? We could not v calculate (a) wlthout a nearly normal population dlstrlbutlon. Wlthout a nearly normal populatlon dlstrlbutlon and a small sample slze of n = 15, the sampling distribution will not v .I be nearly normal. Therefore we could not v .I calculate (c) either