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I have some questions that need answers, please. 1.) Lunch break: In a recent survey of 655 working Americans ages 25-34, the average weekly amount

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I have some questions that need answers, please.

1.)

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Lunch break: In a recent survey of 655 working Americans ages 25-34, the average weekly amount spent on lunch was $45.16 with standard deviation $2.67. The weekly amounts are approximately bell-shaped. Part: 0 / 3 Part 1 of 3 (a) Estimate the percentage of amounts that are between $37.15 and $53.17. (Choose one) of the amounts fall between $37.15 and $53.17. Approximately 68% X 5 Approximately 75% Approximately 95% Approximately 88.9% Almost allNuclear power: The following table presents the number of nuclear reactors as of August 2, 2013, in some countries that had one or more reactors. Country Number of Reactors Country Number of Reactors Argentina Mexico Armenia Netherlands Belgium Pakistan Brazil Romania 2 Bulgaria 2 Russia 33 Canada 19 Slovakia 4 China 18 South Africa Czech Republic 6 South Korea 23 Finland 4 Sweden 10 Germany 9 Ukraine 15 Hungary A United Kingdom 16 Japan 50 Slovenia Send data to Excel Part: 0 / 4 Part 1 of 4 (a) Find the first and third quartiles of these data. The first quartile is The third quartile isGet an education: A survey asked 32,177 people how much confidence they had in educational institutions. The results were as follows. Round your answers to four decimal places if necessary. Response Number A great deal 10,052 Some 17,871 Hardly any 4254 Total 32,177 Send data to Excel Part: 0 / 3 Part 1 of 3 (a) What is the probability that a sampled person has either a great deal or hardly any confidence in educational institutions? The probability that a sampled person has either a great deal or hardly any confidence in educational institutions isDetermine whether the random variable X has a binomial distribution. If it does, state the number of trials n. If it does not, explain why not. Ten cards are randomly drawn with replacement from a standard deck of 52. Let A be the number of Hearts drawn. Part: 0 / 2 Part 1 of 2 The random variable (Choose one) a binomial distribution. has X 5 does not haveCheck our blood pressure: In a recent study, the Centers for Disease Control and prevention reported that diastolic blood pressures of adult women in the United States are approximately normally distributed with mean 80.4 and a standard deviation of 9.5. Round the answers to four decimal places. (a) What proporb'on of women have blood pressures lower than T1? The proportion of women who have blood pressures lower than T1 is D . 'I'Ire lifetimes: The lifetime of a certain type of automobile tire (in thousands of miles) is normally distributed with mean p. = 40 and standard deviation 0 = 5. Use the "IT84 Plus calculator to answer the following. (a) Find the 20th percenle of the tire lifemes. (b) nd the 72nd percentile of the tire lifetimes. (c) Find the third quartile of the tire lifetimes. (d) The tire company wants to guarantee that its tires will last at least a certain number of miles. What number of miles {in thousands) should the company guarantee so that only 3% of the res violate the guarantee? Round the answers to at least two decimal places. The 20th percentile of the re lifetimes is B thousand miles. The 'T2nd percentile of the tire lifetimes is D thousand miles. The third quartile of the re lifetimes is D thousand miles. \fA sample of size 45 will be drawn from a population with mean 53 and standard deviation 11. Use the TI84 Plus calculator. (a) Is it appropriate to use the normal distribution to nd probabilities for E? (b) Find the probability that ; will be between 54 and 55. Round the answer to at least four decimal places. th (c) Find the 47 percentile of 3:. Round the answer to at least two decimal places. 0 It is appropriate to use the normal distribution to find probabilities for E. "he probability that I will be between 54 and 55 is D. "he 47th percentile of; is D. Q It is not appropriate to use the normal distribution to find probabilities for E. TV sets: According to the Nielsen Company, the mean number of TV sets in a U.S. household in 2013 was 2.24. Assume the standard deviation is 1.1. A sample of 95 households is drawn. (a) 1What is the probability that the sample mean number of TV sets is greater man 2? Round your answer to at least four decimal places. The probability that the sample mean number of TV sets is greater than 2 is E]

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