I have the following list.

IPlist= ['209.85.238.4', '216.239.51.98', '64.233.173.198', '64.3.17.208', '64.233.173.238'] 

TO sort this list in ascending order, I was advised to use the following code snippet.

IPlist.sort (key=lambda address:list(map(int, address.split('.')))) 

It works and gives the following output.

['64. 3. 17. 208', '64. 233. 173. 198', '64. 233. 173. 238', '209. 85. 238. 4', '216. 239. 51. 98'] 

It is correct, but I am not sure I understand it. FIrst of all, what is address variable? I havent assigned address variable prior, I only have IPlist.

Example:

list1 = [1,2,3,4] final = list(map(lambda x: x*x, list1)) print(final) 

For eg, in this example I have list1 already defined aboave before mapping to a lambda function that returns the sqaure of the value. But in above function,the address is not defined so where it is getting the valurs from Iplist??

In my example, inside map, I have used the same name list1 which is already defined. If I modify the name, it wont grab the values. Similarly, the variable name of address and IPadress are different.SO how is this working?