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I HAVE THIS PART OF THE NEED HELP ALL THE VALUE NEEDED ARE ATTACHED SO PLEASE SOLVE VERY FAST ! Part 2: In this part

I HAVE THIS PART OF THE NEED HELP ALL THE VALUE NEEDED ARE ATTACHED SO PLEASE SOLVE VERY FAST !

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Part 2: In this part of the lab, you will be calculating the predicted values of the the currents I1, 12 and 13 in a circuit built from your components like that shown in the circuit diagram below. For R1, R2, R3, 841, and 82, use your measured values from the table above in your calculations, not the ideal values. Use the directions for 11, 12 and 13 as given in the circuit diagram. 8 (V) 62 (V) R1 (k0) R2 (k() R3 (k() Ideal 4.5 3.3 4.7 10. 4.7 Measured 4.86 3.2974 4.64 8.87 4.66 % Error 8% 0.078% 1.277% 11.3% 0.851%1) Use Kirehhoffs Loop Law to set up two equations for the left and right loops of the circuit. Eq. for Left Loop: Eq. for Right Loop: 2) Use Kirchhoffs Junction Law applied to one ofthe twojunctions ofthe circuit to arrive at a third equation: Eq. for Junction: Solve these three equations simultaneously to get the calculated currents [L I; and [3 and record them in the table below. Show your work below. (If you struggle with the algebra, a strategyr is to solve the left loop equation for II, solve the right loop equation for 12, and substitute both equations into the junction equation so that this equation is entirely in terms 13. Then solve this latter equation for 13.) I1 (mA) 12 (mA) 13 (mA) Calculated Measured Percent ErrorPurpose: Apply Kirchhoff's Loop and Junction Rules to analyze a circuit and compare the resulting calculated current to measured values. Concepts: To analyze a circuit we may apply Kirchhoff's Rules. The first of these rules, Kirchhoff's Junction Rule, states that the sum of the currents coming into a junction equals the sum of the currents going out of a junction. out This is a statement of conservation of charge (1 A = 1 C/s) in a circuit. The second of these rules, Kirchhoff's Loop Rule, states that the sum of the potential differences around a closed path, or loop, in the circuit is equal to zero. [(AV), = 0 This is a statement of conservation of energy (1 V = 1 J/C) in a circuit

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