I have tried this question a few times and thought I had used the correct equation - evidently, I am either not using the correct equation or simply not getting the numbers correct. Could someone please walk me through this problem?

Use the integration capabilities of a graphing utility to approximate the surface area of the surface of revolution. (Round your answer to four decimal places.) Function Interval Axis of Revolution y = sin x 0 , It 12 x-axis X Need Help? Read It