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I How did he get the value inside the circle 3.2 LEX Evaluate I:(tanx d* -3.2 dx = (sinx)-(0IX) 3.2 (sinx)3:2 3.2 (cosx)2 %3D

I How did he get the value inside the circle 3.2 LEX Evaluate I:(tanx d* -3.2 dx = (sinx)-(0IX) 3.2 (sinx)3:2 3.2 (cosx)"2 %3D %3D 2.

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