I just need the answers for number 7

XV fx =1-BINOM.DIST(6,120,0.15,1) B C D E F G H K M N uns a cell phone kiosk in the mall. On a typical day he serves 120 customers and each have Binomial Probabilities robabilty of a sale. Possible values 1.) P( X - 16) 0.093112269 He sells exactly 16 phones. 16 st wants to calculate the probability of making exactly 16 sales in a given day. 2.) P( x = 16) 0.36042042 He sells at most 16 phones. 0, 1, 2, 3, .., 14, 15, 16 ( x =16). In cell L3, type: -BINOM.DIST[16,120,0.15,0] 3.) P( X > 16) 0.63957958 He sells more than 16 phones. 17, 18, 19, ..., 118, 119, 120 at the binomial distribution formula includes the number of success 16 , then sample size 4.) P( X = 7) 0.001074988 He sells exactly 7 phones. 7 probability of a single success 0.15, and the 0 means that it is not cumulative, but exactly + 5.) P( X $7) 0.001592694 He sells at most 7 phones. 0, 1, 2, 3, 4, 5, 6, 7 6.) P( X > 7) 0.998407306 He sells more than 7 phones. 8, 9, 10, ..., 118, 119, 120 wants to find the probability that he will have at most 16 sales. This means less than or 7.) P(x 27) 0.999482294 He sells at least 7 phones. 7, 8, 9, ..., 118, 119, 120 P( x $ 16). In cell L4, type: =BINOM.DIST(16,120,0.15,1) lative is changed to 1. This means all of the outcomes from 0 to 16 are included. e wants to find the probability that more than 16 sales are made in the day. The formula the left tailed value, so we need to adjust by typing in 1 minus the formula for a right tail In cell L5, type: =1-BINOM.DIST(16,120,0.15,1) the examples above to complete the probabilities. #7 is a bit different because "at least" value and "more than" does not