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I just want the final answer, I have only 10 minutes Question 1 If 50 mole KMnO4, 100 mole Hg2Cl2 and 500 mole HCl were
I just want the final answer, I have only 10 minutes
Question 1 If 50 mole KMnO4, 100 mole Hg2Cl2 and 500 mole HCl were used for the following process, 2KMnO4 +5Hg2Cl2 + 16HCI > 10HgCl2 + 2MnCl2 + 2KCI + 8H20 The excess reactant would be. KMnO4 HCI MnCl2 Hg2012 HgCl2 Step by Step Solution
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