I know this cant be right but I am not sure where my mistake is

(IT) use linear cupproximation of f ( x ) = sin (x ) at x = it to approximate sin ( 183") L ( x ) = f ( TT ) + f ( TT ) ( X - TT - 3. 1416 f ( x ) = sin ( x ) -> f ( 15 ) = sin ( 17 ) = 0 f ( x ) = Cos ( x ) -f' ( TP ) = cos ( IT ) = - 1 L ( x ) = 0+ ( - 1) ( x - 7 ) = - 1(x ) + (x- 1 ) +0