I need a python code that returns a copy of the tuple but only with "fixed points"as defined below. I$\text{'}$m very limited in what functions I can use, I$\text{'}$m using a find$\_$tup function below $($the introcs module works with basic functions, but I have to use it instead of something like "find.x$").$ I'll attatch a picture with my wrong answer $($it$\text{'}$ll show my results on the bottom left$).$ I cannot use the "append" tool for this function. I think I might be wrong about using the find feature, too. Any idea of what direction I should try next?

Implement fixed$\_$points

Read the specification of the function

fixed$\_$points in the module funcs. Implement

this function according to its specification. This is a

function where it is particularly helpful to look at

the examples and test cases.

When you have implemented the function, test

your answer with the test script. You should now

pass all tests.

Check the Function

You may run this test multiple times.

LAST RUN on $5/9/2024,17$:$13$:$35$ PM

The call fixed$\_$points $((0,3,2))$ returns $,$

$2.$

def fixed$\_$points$($tup$)$:

$"""$

Returns a copy of tup, including only the "fixed points".

A fixed point of a tuple is an element that is equal to its position in the tuple.

For example $0$ and $2$ are fixed points of $(0,3,2).$ The fixed points are returned in

the order that they appear in the tuple.

Examples:

fixed$\_$points$((0,3,2))$ returns $(0,2)$

fixed$\_$points$((0,1,2))$ returns $(0,1,2)$

fixed$\_$points$((2,1,0))$ returns $(1,)$

Parameter tup: the tuple to copy

Precondition: tup is a tuple of ints