I need help answering what the 98% interval be.

Reference: My Homework

A company surveyed 2200 men where 1078 of the men identified themselves as the primary grocery shopper in their household. a) Estimate the percentage of all males who identify themselves as the primary grocery shopper. Use a 98% confidence interval. Check the conditions first. b) A grocery store owner believed that only 43% of men are the primary grocery shopper for their family, and targets his advertising accordingly. He wishes to conduct a hypothesis test to see if the fraction is in fact higher than 43%. What does your confidence interval indicate? Explain. c) What is the level of significance of this test? Explain. a) Check the conditions for constructing a confidence interval. Select all necessary conditions that have the appropriate explanation below. A. Success/Failure Condition: This condition is not satisfied because there were fewer than either 10 successes or failures. B. Nearly Normal Condition: This condition is satisfied because there is nothing to indicate that the underlying population is not Normal. LY C. Randomization Condition: This condition is satisfied because there is nothing to indicate that the samples were not drawn randomly. LY D. Success/Failure Condition: This condition is satisfied because there were more than 10 successes and failures. E. 10% Condition: This condition is not satisfied because 2200 men are more than 10% of the population of men. LY F. 10% Condition: This condition is satisfied because 2200 men are less than 10% of the population of men. G. Nearly Normal Condition: This condition is not satisfied because it is highly unlikely that the population of men is Normal. H. Randomization Condition: This condition is not satisfied because the samples were drawn from a convenience sample Construct a 98% confidence interval for the sample proportion. The 98% confidence interval is (). (Round to three decimal places as needed.)