I need help finding the PW of Design B, the other answers are correct

A new highway is to be constructed. Design A calls for a concrete pavement costing $80 per foot with a 16-year life; three paved ditches costing $5 per foot each; and four box culverts every mile, each costing $8,000 and having a 16-year life. Annual maintenance will cost $1,600 per mile; the culverts must be cleaned every four years at a cost of $300 each per mile. Design B calls for a bituminous pavement costing $50 per foot with a 8-year life; two sodded ditches costing $1.30 per foot each; and two pipe culverts every mile, each costing $2,150 and having a 8-year life. The replacement culverts will cost $2,400 each. Annual maintenance will cost $2,600 per mile; the culverts must be cleaned yearly at a cost of $225 each per mile; and the annual ditch maintenance will cost $1.60 per foot per ditch. Compare the two designs on the basis of equivalent worth per mile for a 16-year period. Find the most economical design on the basis of AW and PW if the MARR is 10% per year. Click the icon to view the interest and annuity table for discrete compounding when the MARR is 10% per year. The AW value for Design A is $ - 70052.68 /mi. (Round to the nearest hundreds.) The PW value for Design A is $ - 548071.15 /mi. (Round to the nearest hundreds.) The AW value for Design B is $ - 72833.13 /mi. (Round to the nearest hundreds.) The PW value for Design B is $ /mi. (Round to the nearest hundreds.) N 1 2 3 4 5 Discrete Compounding; i = 10% Single Payment Uniform Series Compound Compound Sinking Amount Present Amount Present Fund Factor Worth Factor Factor Worth Factor Factor To Find F To Find P To Find F To Find P To Find A Given P Given F Given A Given A Given F FIP PIF FIA PIA AIF 1.1000 0.9091 1.0000 0.9091 1.0000 1.2100 0.8264 2.1000 1.7355 0.4762 1.3310 0.7513 3.3100 2.4869 0.3021 1.4641 0.6830 4.6410 3.1699 0.2155 1.6105 0.6209 6.1051 3.7908 0.1638 1.7716 0.5645 7.7156 4.3553 0.1296 1.9487 0.5132 9.4872 4.8684 0.1054 2.1436 0.4665 11.4359 5.3349 0.0874 2.3579 0.4241 13.5795 5.7590 0.0736 2.5937 0.3855 15.9374 6.1446 0.0627 2.8531 0.3505 18.5312 6.4951 0.0540 3.1384 0.3186 21.3843 6.8137 0.0468 3.4523 0.2897 24.5227 7.1034 0.0408 3.7975 0.2633 27.9750 7.3667 0.0357 4.1772 0.2394 31.7725 7.6061 0.0315 4.5950 0.2176 35.9497 7.8237 0.0278 5.0545 0.1978 40.5447 8.0216 0.0247 5.5599 0.1799 45.5992 8.2014 0.0219 6 Capital Recovery Factor To Find A Given P AIP 1.1000 0.5762 0.4021 0.3155 0.2638 0.2296 0.2054 0.1874 0.1736 0.1627 0.1540 0.1468 0.1408 0.1357 0.1315 0.1278 0.1247 0.1219 7 8 9 10 11 12 13 14 15 16 17 18 A new highway is to be constructed. Design A calls for a concrete pavement costing $80 per foot with a 16-year life; three paved ditches costing $5 per foot each; and four box culverts every mile, each costing $8,000 and having a 16-year life. Annual maintenance will cost $1,600 per mile; the culverts must be cleaned every four years at a cost of $300 each per mile. Design B calls for a bituminous pavement costing $50 per foot with a 8-year life; two sodded ditches costing $1.30 per foot each; and two pipe culverts every mile, each costing $2,150 and having a 8-year life. The replacement culverts will cost $2,400 each. Annual maintenance will cost $2,600 per mile; the culverts must be cleaned yearly at a cost of $225 each per mile; and the annual ditch maintenance will cost $1.60 per foot per ditch. Compare the two designs on the basis of equivalent worth per mile for a 16-year period. Find the most economical design on the basis of AW and PW if the MARR is 10% per year. Click the icon to view the interest and annuity table for discrete compounding when the MARR is 10% per year. The AW value for Design A is $ - 70052.68 /mi. (Round to the nearest hundreds.) The PW value for Design A is $ - 548071.15 /mi. (Round to the nearest hundreds.) The AW value for Design B is $ - 72833.13 /mi. (Round to the nearest hundreds.) The PW value for Design B is $ /mi. (Round to the nearest hundreds.) N 1 2 3 4 5 Discrete Compounding; i = 10% Single Payment Uniform Series Compound Compound Sinking Amount Present Amount Present Fund Factor Worth Factor Factor Worth Factor Factor To Find F To Find P To Find F To Find P To Find A Given P Given F Given A Given A Given F FIP PIF FIA PIA AIF 1.1000 0.9091 1.0000 0.9091 1.0000 1.2100 0.8264 2.1000 1.7355 0.4762 1.3310 0.7513 3.3100 2.4869 0.3021 1.4641 0.6830 4.6410 3.1699 0.2155 1.6105 0.6209 6.1051 3.7908 0.1638 1.7716 0.5645 7.7156 4.3553 0.1296 1.9487 0.5132 9.4872 4.8684 0.1054 2.1436 0.4665 11.4359 5.3349 0.0874 2.3579 0.4241 13.5795 5.7590 0.0736 2.5937 0.3855 15.9374 6.1446 0.0627 2.8531 0.3505 18.5312 6.4951 0.0540 3.1384 0.3186 21.3843 6.8137 0.0468 3.4523 0.2897 24.5227 7.1034 0.0408 3.7975 0.2633 27.9750 7.3667 0.0357 4.1772 0.2394 31.7725 7.6061 0.0315 4.5950 0.2176 35.9497 7.8237 0.0278 5.0545 0.1978 40.5447 8.0216 0.0247 5.5599 0.1799 45.5992 8.2014 0.0219 6 Capital Recovery Factor To Find A Given P AIP 1.1000 0.5762 0.4021 0.3155 0.2638 0.2296 0.2054 0.1874 0.1736 0.1627 0.1540 0.1468 0.1408 0.1357 0.1315 0.1278 0.1247 0.1219 7 8 9 10 11 12 13 14 15 16 17 18