i need help for the three questions

Use the standard reduction potentials located in the 'Tables' linked above to calculate the equilibrium constant for the reaction: Sn2+(aq)+2Fe2+(aq)Sn(s)+2Fe3+(aq) Hint: Carry at least 5 significant figures during intermediate calculations to avoid round off error when taking the antilogarithm. K= G for this reaction would b than zero. No more group attempts remain Use the standard reduction potentials located in the 'Tables' linked above to calculate the equilibrium constant for the reaction: 2Ag+(aq)+Ni(s)2Ag(s)+Ni2+(aq) Hint: Carry at least 5 significant figures during intermediate calculations to avoid round off error when taking the antilogarithm. K= G for this reaction would be than zero. Use the standard reduction potentials located in the 'Tables' linked above to calculate the equilibrium constant for the reaction: I2(s)+2Cr2+(aq)2I(aq)+2Cr3+(aq) Hint: Carry at least 5 significant figures during intermediate calculations to avoid round off error when taking the antilogarithm. K= G for this reaction would be than zero. Use the standard reduction potentials located in the 'Tables' linked above to calculate the equilibrium constant for the reaction: Sn2+(aq)+2Fe2+(aq)Sn(s)+2Fe3+(aq) Hint: Carry at least 5 significant figures during intermediate calculations to avoid round off error when taking the antilogarithm. K= G for this reaction would b than zero. No more group attempts remain Use the standard reduction potentials located in the 'Tables' linked above to calculate the equilibrium constant for the reaction: 2Ag+(aq)+Ni(s)2Ag(s)+Ni2+(aq) Hint: Carry at least 5 significant figures during intermediate calculations to avoid round off error when taking the antilogarithm. K= G for this reaction would be than zero. Use the standard reduction potentials located in the 'Tables' linked above to calculate the equilibrium constant for the reaction: I2(s)+2Cr2+(aq)2I(aq)+2Cr3+(aq) Hint: Carry at least 5 significant figures during intermediate calculations to avoid round off error when taking the antilogarithm. K= G for this reaction would be than zero