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I need help in step 4. Please show steps i got stuck. Thanks Part 1 of 5 The breaking strength of hockey stick shafts made

I need help in step 4. Please show steps i got stuck. Thanks

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Part 1 of 5 The breaking strength of hockey stick shafts made of two different graphite-kevlar composites yields the following results (in Newtons): Composite 1: 478.9 456.7 485 491.3 489.8 502.2 484.5 520.6 482.8 515.1 458. 1 492.3 495 484.5 492.4 504.1 485.8 507.5 498.6 505 (Note: The average and the standard deviation of the data are respectively 491.51 Newtons and 16.085 Newtons.) Composite 2: 507.3 474.7 484.9 473.2 469.9 482.4 449 479.8 445. 1 458 463.4 (Note: The average and the standard deviation of the data are respectively 471.61 Newtons and 17.651 Newtons.) Use a 1% significance level to test the claim that the standard deviation of the breaking strength of hockey stick shafts made of graphite-kevlar composite 1 is different from the standard deviation of the breaking strength of hockey stick shafts made of graphite-kevlar composite 2. If normality plots are not provided assume that the samples are from normal populations. Procedure: Two variances F Hypothesis Test Assumptions: (select everything that applies) Normal populations The number of positive and negative responses are both greater than 10 for both samples Simple random samples Population standard deviations are unknown but assumed equal Sample sizes are both greater than 30 Population standard deviation are unknown Population standard deviations are known Paired samplesPart 2 Step 1. Hypotheses Set-Up: where |o's are To the Ho: OFF/0: - 1 - G population means V X and the units are |N Ha: 01-101 and the test is Two Tail 1 part 3 of Step 2. The significance level a - 1 6- 35 Step 3. Compute the value of the test statistic: X o" = 0.834 (Round the answer to 3 decimal places) Part 4 of 5 Step 4. Testing Procedure: (Round the answers to 3 decimal places) CVA PVA Provide the critical value (s) for the Rejection Region: Compute the P-value of the test statistic: left CV is of and right CV is P-value is 0.696 / of Step 5. Decision: CVA PVA Is the test statistic in the rejection region? Is the P-value less than the significance level? no v 6 Conclusion: Do not reject the null hypothesis in favor of the alternative. ~ Show Detailed Solution Question Help: Video Written Example Messag

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