I need help solving this.

Use a change of variables or the table to evaluate the following indefinite integral. [ ( x 12 - 4x 3 ) 4 ( x 19 - x2 ) dx Click the icon to view the table of general integration formulas. [ ( x 12 - 4x 3) 4 ( x 1 1 - x 2 ) dx = General Integration Formulas cos ax dx = - sin ax + C sin ax dx = - - cos ax + C sec 2 ax dx = - tan ax + C csc 2 ax dx = - 1 - - cotax + C sec ax tan ax dx = - sec ax + C cscax cotax dx = - - cscax + C e ax dx = - eax + C a In b [b * dx = = b * + C , b > 0 , b # 1 dx 1 -12+C dx - tan = sin -1_+ C, a>0 a2 + x 2 a a Vaz -x2 a dx - sec =+ C , a > o x1x2 - a2