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I need help with these exercises. I am stuck. Ty - I do not have anything more. That is why I need help. Question #1

I need help with these exercises. I am stuck. Ty - I do not have anything more. That is why I need help.

Question #1

  1. Find each value requested for the distribution of scores in the following table. Be sure to show all formulas with symbols (and plug-in numbers), steps, processes, and calculations for all parts of all answers above.
X f
7 3
6 5
5 4
4 2
3 3
  1. a. n b. f (sum of f) c. X2 (sum of x squared)

My answer:

n = 5 b.f (sum of f)= 17 c.X2(sum of x squared) = 135

X

f

Cumu. f

x2(x *x)

7

3

3

49

6

5

8

36

5

4

12

25

4

2

14

16

3

3

17

9

f = 17

X2= 135

n =The number of x values = 5 b.f (sum of f)= 3 + 5 + 4 + 2 + 3 = 17 c.X2(sum of x squared) = (7*7) + (6*6) + (5*5) + (4*4) + (3*3) = 135

MyProfessor'ss correction:

Part b is correct. Parts a and c are related. Hint: Every occurrence of... See if you can solve it. You can reply to this thread with updated answers.

Question #2

Construct a grouped frequency distribution table to organize the following set of scores: 716, 943, 827, 712, 586, 685, 684, 520, 592, 192, 590, 884, 742, 520, 791, 690, 483, 473, 450, 280, 380, 450, 506, 112. Be sure to explain the logic behind your grouping sizes/ranges along with showing the actual frequency distribution table. Note, you can use the table function in your Canvas discussion posting toolbar.

My answer:

To construct a grouped frequency distribution table, we first need to determine the range of the data, the number of classes (groups), the width of each class, and the class boundaries.

Range: The range is the difference between the highest and lowest scores. In this case, the highest score is 943, and the lowest is 112. So, the range is 943 - 112 = 831.

Number of Classes: A common rule of thumb is to start with approximately 5 to 20 classes. For this example, l use ten classes.

Class Width: The class width is the range divided by the number of classes. In this case, the class width is 831 / 10 = 83.1, so we can't have a fraction of a score. I round this up to 84.

Class Boundaries: The class boundaries are the actual ranges of scores that fall into each class. So, our class width is 84. The first class will be 112 - 195, the second class will be 196 - 279, and so on.

Here is the grouped frequency distribution table:

Score Range Frequency 112 - 195 1 196 - 279 1 280 - 363 1 364 - 447 2 448 - 531 3 532 - 615 3 616 - 699 4 700 - 783 3 784 - 867 2 868 - 951 4

The logic behind the grouping sizes/ranges is to ensure that each class has an equal width, which makes it easier to compare the frequencies of different classes. The number of classes is chosen to balance having enough classes to show the distribution of scores and not having too many, making the table challenging to interpret.

MyProfessor'ss comment: Overall, there is solid logic with the groupings. I would just recommend going with cleaner divisions (i.e. groupings of 100) for ease of interpretation.

Question #4

Find each value requested for the distribution of scores in the following table. Be sure to explain the process of each problem in writing and show all math steps/processes/calculations.

X f
6 4
5 4
4 2
3 3
2 6

n f (sum of f) X2 (sum of x squared)

X

f

Cumu. f

x2(x *x)

6

4

4

36

5

4

8

25

4

2

10

16

3

3

13

9

2

6

19

4

f = 19

X2 = 90

n = 5 f (sum of f) = 19 X^2 (sum of x squared) = (6*6) + (5*5) + (4*4) + (3*3) + (2*2) = 90

See my reply above to number one. The same feedback applies here.

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