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I need help with this part Is this result consistent with what you discovered in 1, 2, and 3? Discuss if this equation is valid

I need help with this part

"Is this result consistent with what you discovered in 1, 2, and 3? Discuss if this equation is valid based on what you see in all the graphs. It will be appropriate to graph

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\ftranslate.google.com OFF ... Chapter 6 Lab - Saved to my Mac W Design Layout References Mailings Review View ? Tell me Comments Editi Therefore, you now have to take the same data that you collected, when you graphed T vs. Length, but now take the square root of the length, and graph T vs. VL, according to Galileo's equation your slope should be Y = mx T = VL Is this result consistent with what you discovered in 1, 2, and 3? Discuss if this equation is valid based on what you see in all the graphs. It will be appropriate to graph T vs.VL graph and find the slope of the trendline for your discussion. Now if you slope is equal to the below expression, then you will take your slope and calculate an experimental value for g. Compare that experimental value to the accepted value of g which is 9.8m/s^2 and calculate the percent error. Comment on that percent error in your conclusion. words x English (United States) Accessibility: Investigate Focus EO TE English (United States) Wx Accessibility: Investigate Focus ES MAR 31 MacBook Pro IC * de LO CO CO1. AaBbCc[ a. AaBbCc[ AaBbCcDdEe AaBbCcDdEe Aa BbCcD = Items (numb.. Items (numb.. Normal No Spacing Heading 1 that relationship if you need to So, if you create a graph, don't bother applying a linear fit in Excel because it will be a square root curve not a linear curve. Length (m) vs. Oscillation Period (s) y= 1.4782x + 0.618s N Oscillation Period (s) New.... .. ............... ... .. .. O 0.2 0.4 0.6 10.8 1.2 Length (m ) Font According to the formula for the period of a simple pendulum, T = 2TTV(L/g), where T is the period of oscillation, L is the length of the pendulum, and g is the acceleration due to gravity. From this formula, it is clear that the period T of a pendulum is dependent on its length L. As we can see that the period T is directly proportional to the square root of the length L of the pendulum. Therefore, as the length L of the pendulum increases, its period T also increases. This relationship between the period and length of the pendulum is a fundamental property of simple harmonic motion and has been demonstrated experimentally for centuries. To conclude, we can say that the period T of a pendulum depends on the length L of the pendulum. Accessibility: Investigate Focus MacBook ProIN 1. AaBbCcl a. AaBbCc[ AaBbCcDdEe AaBbCcDdEe AaBbCcDc Items (numb.. Items (numb.. Normal No Spacing Heading 1 also increase. 2. Measure the oscillation period T with different angles (30 or less), using any method available. Keep the mass and string length constant. Angle of Oscillation Motion Period (s) (degree) Trial 1 1.68 Trial 2 1.68 Trial 3 1.68 Trial 4 1.69 Trial 5 1.70 3. Graph period T as a function of angle 0. T goes on the y axis and angle goes on the x axis. Make sure that you can see the zero, zero on both axis of the graph. Oscillation Period vs Angle of Motion y = 0.001x + 1.666s Font Oscillation Period (s) O 20 25 30 35 in 9 Angle of Motion Focus Accessibility: Investigate MacBook Pro - NM ICw New Microsoft Word Document nces Mailings Review View Tell me 2 - V a v IN 1. AaBbCc[ a. AaBbCc[ AaBbCcDdEe AaBbCcDdEe AaBbCcDc Items (numb. Items (numb. Normal No Spacing Heading 1 Oscillation VLength (m) Period (s) Trial 1 0.316 0.62 Trial 2 0.447 0.90 Trial 3 0.547 1.10 Trial 4 0.632 1.28 Trial 5 0.707 1.43 Trial 6 0.774 Trial 7 0.836 1.70 Trial 8 0.894 Trial 9 0.948 1.91 Trial 10 H 2.00 sqrt(Length) (m) vs. Oscillation Period (s) y = 2.0251x - 0.007s N N Font Oscillation Period (s) .. ........7.... . ........ . 0.2 0.4 0.6 0.8 1.2 sqrt(Length) Accessibility: Investigate E Focus MacBook ProAa Pp 1. AaBbCc[ a. AaBbCc[ AaBbCcDdEe AaBbCcDdEe AaBbCCD DV AV Items (numb... Items (numb.. Normal No Spacing Heading 1 m? The result of this experiment should be a graph of period vs mass. I think that if we increase the mass of an object in simple harmonic motion will increase the period T, and decreasing the mass will decrease the period. b. Measure oscillation period T with different masses, using any method available. Keep the initial angle and string length constant. Mass of Oscillation weight (kg) Period (s) Trial 1 Trial 2 Trial 3 Trial 4 Trial 5 c. In Excel, graph period T as a function of mass m. T goes on the y axis and m goes on the x axis. Make sure that you can see the zero, zero on both axis of the graph. Oscillation Period vs Mass y = 1.7 Font 1.2 Oscillation Period (s) 0.6 0.4 0.2 O 0.2 0.4 0.6 0.8 1.2 1.4 1.6 Mass m (kg) What do you conclude from the graph? Does it match your expectations? (Discuss!) States) Ux Accessibility: Investigate Focus MacBook Prow. New Microsoft Word Document Design Layout References Mailings Review View Table Design >> Tell me Comm Indent v 2- Line Numbers v Spacing Left Before: 0 pt ( > mns Breaks be Hyphenation v Position Wrap Bring Send = Right: After: Op Text Forward Backward Oscillation VLength (m) Period (s) Trial 1 0.316 0.62 Trial 2 0.447 0.90 Trial 3 0.547 1.10 Trial 4 0.632 1.28 Trial 5 0.707 1.43 Trial 6 0.774 1.57 Trial 7 0.836 1.70 Trial 8 0.894 1.80 Trial 9 0.948 1.91 Trial 10 2.00 English (United States) fox Accessibility: Investigate Focus 1!! E MAR 253 37 CO x MacBook Pro IC1. AaBbCc[ a. AaBbCc[ AaBbCcDdEe AaBbCcDdEe E Ev Items (numb.. Items (numb.. Normal No Spacing I would say that if we will increase the Length then the Period will increase too. b. Measure the oscillation period T with different lengths L. You will need to use many values for length to get this graph correct. Use some lengths that are as small as the simulation will allow and some that are as large as it will allow. It may take as many as 10 trials for you to get this curve to have the right shape Oscillation Length (m) Period (s) Trial 1 0.10 0.62 Trial 2 0.20 0.90 Trial 3 0.30 1.10 Trial 4 0.40 1.28 Trial 5 0.50 1.43 Trial 6 0.60 1.57 Trial 7 0.70 1.70 Trial 8 0.80 1.80 Trial 9 0.90 1.91 Trial 10 1.00 2.00 Graph period T as a function of length L. T goes on the y axis and length goes on the x axis. Make sure that you can see the zero, zero on both axis of the Font graph. Email me if you can't do this. This part is important! Do not assume that this is a straight line. I'll go ahead and tell you that there is a relationship here but NOT a linear relationship. It is a square root curve. Google that and research Accessibility: Investigate Focus MacBook Pro

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