I need help with this, please!

Casell. 9: =9, = +9 /C and q =q. =-9 /C. qa X Oq (d) In your notebook, draw the forces on q due to 9. 9,. 9, and q.. Or use the result of of Homework: Charges on a Square Free Body Diagram. (e) Due to symmetry the direction of the net force is D. In the -y direction. v Hint: For each force draw the x and y components. Some will add and some will cancel. (f) Calculate the magnitude of the force on the charge q, given that the square is 10.0 cm on a side and q = 2.5 pc. Fnet = 82.65 XVN1. Three charges are shown in the configuration below. YA -2q a a X q q (a) In your notebook, draw a free body diagram of the forces on charge on the lower right corner of the triangle. Note: If you use the sin and cos functions with angles in degrees such sin(10") the degree sign is required. Use the degree symbol from the mathtype editor as shown on the image below. (b) The force of -2q on lower-right q is F = Vi+ VIN Note: Write your answer in terms of q, k, and a. (c) The force of lower-left q on lower-right q is F = Vi+ ViN Note: Write your answer in terms of q, k, and a. (d) What is the net electric force on the charge located at the lower right-hand corner of the triangle shown here? Note: Write your answer in terms of q, k, and a. Fner = VIN (e) If q = 4 nC and a = 5 um, calculate the magnitude of the net force and the angle the the net force makes counter-clockwise with the x-axis. Use k = 9 x 109 Nm2C2 Fnet = VN Angle counter-clockwise from the x-axis =1. Two point-charges Q1 and Q2 are 2.6 m apart, and their total charge is 36/C. If the force of repulsion between them is 0.3976 N, what are magnitudes of the two charges by following the steps below? (a) Q1 + Q2 = 36x10-V C Use Coulomb's Law to calculate the product of the two charges. (b) Q1 x Q2 = 2.99 x 10-10V CZ (c) Solve for Q2 and Q, using the two equations you got in part (a) and part (b). Hint: There are two possible solutions. Enter the answer with curly brackets as {Q1,Q2) where Q, is the smaller charge and Q2 is the larger charge. (C) {Q1,Q2) = (1 x10-5,4.6 x10 -5 x V C