I need help!

You are performing an experiment using the force table shown in the image at right. The string through which tension force 1 acts has a mass of 0.4 kg suspended from it at an angle of 165 relative to the "x" axis or 0 degree mark as 10/ 100 90 420 60 shown in the image. The string through which 140 130 tension force 2 acts has a mass of 1 kg suspended 160 160 from it at an angle of 240. What is the direction of FT1 OL tension force 3 (not shown on the image) that is 0 required to achieve static equilibrium? Though OSE you are giving your result in some number of 720 210 200 190 180 170 degrees, please do not include "degrees" in symbol or word, in your answer. Otherwise, your answer OLE OLE OFF FTR will be counted as incorrect. Please enter numerical answers only. Give your answer to two sig. figs