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I NEED ONLY PARTS G,H,I,J,K,L,M PLEASE Problem 86. (20 pts) Consider a thin transparent film of index of refraction ng=1.20 and thickness d=100 nm. This
I NEED ONLY PARTS G,H,I,J,K,L,M PLEASE
Problem 86. (20 pts) Consider a thin transparent film of index of refraction ng=1.20 and thickness d=100 nm. This film coats a transparent material of index of refraction nm = 1.44. Consider light of wavelength 480 nm in air incident normally on the thin film from air of index na = 1.00. Recall that the amplitude reflection coefficient for normal incidence from medium 1 to medium 2 is r=ni -n2. Take the electric field incident on the film to be E = (2000 V/m) cos(wt) ni+n2 A) Show that the chosen indices of refraction satisfy the relation ng= anm. B) Find the wavelength of light in the film. C) Show that the chosen film thickness satisfies d= \f/4, where if is the wavelength of the light in the film. D) Find the reflection coefficient for the air-to-film interface. Call this r1. E) Find the reflection coefficient for the film-to-air interface. Call this r. F) Find the reflection coefficient for the film-to-material interface. Call this r2. G) It turns out that energy conservation requires that the transmission coefficient 1 through the air to film interface must be such that +2=1-r. Find 72. H) The electric field reflected directly at the air to film interface is Eo=r E. Find Eo. I) The electric field heading to the left from the air film interface that has entered the film, reflected from the film and then exited the film back into the air is E1=Tr2T (2000 V/m) cos(wt+kf (2d)). Find E1. (Recall that cos(wt+T)= -cos(wt) and kf=2 TT / If.) J) The electric field that enters the film and makes two round trips through the film before exiting to the left is E2= Tr2r1 r27 (2000 V/m) cos(wt+kf (4d)). Find E2. K) Note that the electric field that enters the film and makes N round trips through the film before exiting to the left is En=tr2 (r r2)N-17 (2000 V/m) cos(wt+kf (2 Nd)). Find and simplify En. 3 L Find Eo + EN N=1 M) Show that the total reflected field is exactly zero. That is show that Er=Eo+ En=0. Hint: N=1 N 1 CStep by Step Solution
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