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I need solve this question Differentiate. sin(e f(0) = . Q1 1 + cos(0) f'(e) = Use the Intermediate Value Theorem to show that there

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I need solve this question

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Differentiate. sin(e f(0) = . Q1 1 + cos(0) f'(e) = Use the Intermediate Value Theorem to show that there is a root of the given equation in the specified interval. ex = 7 - 6x, (0, 1) Q2 The equation ex = 7 - 6x is equivalent to the equation f(x) = ex - 7 + 6x = 0. f(x) is continuous on the interval [0, 1], f(0) = , and f(1) = Since -Select- >

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