I need some helping to solve these calculus problems, I know its partial fraction integration, but all my answers have been wrong;

a)

We wish to compute 2 31 + 4 dr . TO + 91 (i) We begin by noting that 23 + 91 = 1(x +9) where r"+ 9 is a polynomial of degree two with no real roots. We can thus write 3r + 4 A BI + C + 12 + 9 Give the exact values of A, B and C. A = Number B = Number and C= Number (ii) Finally, we use this partial fraction decomposition to compute the integral. Give its approximate value to 3 decimal places. 2 31+ 4 Number 13 + 91We wish to compute 12 +1 di . 13 + 412 - 161 - 64 (i) We begin by factoring the denominator of the rational function. We get 13 + 412 - 16x -64 = (x - a) (x -b)2 for a # b . What are a and b ? FORMATTING: Make sure b corresponds to the factor of the denominator that repeats twice. a = Number b= Number (ii) Next, we express the fraction in the form 12 +1 A 13 + 412 - 161 - 64 b (I - b)2 Give the exact values of A , B and C. FORMATTING: Make sure A, B, and C correspond to the appropriate denominators, as given in the above setup. A = B = C = (iii) Finally, we use this partial fraction decomposition to compute the integral. Give its approximate value with 3 decimal places. 12 + 1 dr s Number 23 + 472 - 161 - 64