I only need answers to part 2 questions 2, 4, 5, 6. Thank you so much! :)

The rest of the pics are for background.

Force diagram I Sha stab imgeos O mysingh To vig . force of gravity ( my ) is vertically downward . Normal force CN) is perpendicular to he surface components of force of gravity masings is along he force macos O is perpendicular to su face ( V)2 Isle Shah The components of force of granly (my ) are . masin@ - which provides motion This is parallel component OF force of grand . macosQ - is perpendicular component of force of gravity to he ramp . FBD Force diagram macos Q masino my Los Qisher Slash The force F is applied on he blocks to pull it up on the incline Force diagram : masing FBD : IN - OF F = masin Q - object is at rest on the ramp 1=>mgSince -> Object is moving / pulled upward on he ramp .like Shah In the given picture he parallel components of force of gravity polling he cart downward with force masino when there is no friction with an cecceleration is a = masino | a = asino FBD force diagram IN mgcoso mysin Q macoso masing is parallel to he some slope along downward.v Part 1: Preliminary Questions Let's begin by exploring what we already know about force and motion, and how our knowledge can help us in this activity. 1. Imagine an object, a skateboarder, for example, rolling down a hill. Draw a force diagram of the skateboarder. Assume for now that there is no friction between the skateboard and the hill. You can take a picture of your force diagram with your phone and upload it using the image upload tool on the menu above your answer box. Hint: 1. the normal force on an object by a surface is always perpendicular to the surface. 2. the force of gra vity is always directly downward. Score: 0/5 2. Our goal in this activity is to explore the force that seems to pull an object down the ramp, that is, parallel to the ramp surface. But your force diagram does not have a force in this direction. Let's explore why. Notice that the force of gravity is neither parallel to, nor perpendicular to, the ramp surface. Try to add two more force vectors to your force diagram that break the force of gravity into components parallel to and perpendicular to the ramp surface. Score: 0/5 3. Add second a force to your force diagram, this time directed parallel to the ramp surface but pointed up the ramp. Make the magnitude of the force such that it that would cause the skateboarder to move with constant velocity. BIE EEEE oIZI Score: 0/ 2 4. Use your force diagram and your previous experience with equilibrium to answer this. What is the magnitude of the component of the force of gravity that is pulling the cart downward, parallel to the ramp surface in the the situation pictured below? Ramp Forces: Parallel to R Score: 0/2 v Part 2: Create a Model The video below shows a lowfriction cart on a track. As the track is tilted, a force gauge shows the string tension required to hold the cart in place. .1 pivot 0 I4 y u '33: 1. The instructions in the next question will help you use the data table and graph below to create your mathematical model. Angle Tension Degrees Theta N 1 o o 2 - 7 2.7 3 - 14 5 4 - 2 1 8 5 ' 28 10.4 6 35 12.6 0 Saved Tension (N) vs Angle (degress) V 14 12 10 8 Tension (N) 6 4 2 5 10 15 20 25 30 35 Angle (Degrees) Display Curve Fit Uncertainties Tension Curve: F = ATheta + B A : 0.364 Degrees N B : 0.0857 N RMSE : 0.214N r : 0.9992. Collect data that shows the force, Fof the string tension as a function of the ramp angle, 6. That is, we are looking for the function F(9)=?. Linearize your graph to try to find the relationship (equation) that best describes how the force varies as the angle changes. BIEEE I'I I'I \"BEE Score: 0/2 3. Let's do a test of this relationship called extrapolation. We'll use the model to predict what would happen if we examine beyond the range of this dat set. Use your function to answer these questions: 4. Use your function to predict the force on the force sensor when the ramp angle is 90 degrees. To do this, use the force diagram from part 1, but modified for when the ramp is tipped up 90 degrees. To make your prediction, assume a cart mass of 2.25 kg. BIEEEEEEEEI Score: 0/5 5. Extrapolate even farther. According to your model, what would happen if the ramp angle was increased beyond 90 degrees? Do you think the behavior of your model matches how you think the force sensor would read if the ramp was tipped beyond 90 degrees? BIU i555 I'l IAI 0EEI % Score: 0/2 6. Let's assume you are unhappy with the fit you have -- you find that although it fits the data you collected, it does not match with your expectations of how the force shauldvary with the ramp angle. Name some strategies you could use to improve the situation, and help you determine the best function to fit this situation. B IE 55:: al % Score: 0/1 Lock Answer and Continue