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(I re-posted it so a real expert can answer), these questions have long solutions. Q3. Refrigerant R-134a is a common type of refrigerant to use
(I re-posted it so a real expert can answer), these questions have long solutions.
Q3. Refrigerant R-134a is a common type of refrigerant to use in air-conditioning, refrigeration, and heat pump systems. In this question, we want to see how well this fluid can be modelled using the ideal gas law. To determine this, complete the following: a) Determine the compressibility of R-134a at 1.6 MPa and 70 C using: i. only data from tables in the Equations and Data Booklet. ii. the compressibility chart on page 22 of the Equations and Data Booklet (plus any data you need from tables to use this chart). b) Can the density of R-134a be calculated using the ideal gas law within 5% accuracy? c) Determine the change in specific enthalpy for R-134a at 1.6 MPa when the temperature changes from 70C to 100 C when: i. assuming that R-134a is an ideal gas with a constant heat capacity of 0.8367 kJ/kg.K (which is the ideal gas heat capacity at 300 K). ii. using the property tables. d) What are two reasons for the difference in answers between (i) and (ii) for part (c)? Q3. Refrigerant R-134a is a common type of refrigerant to use in air-conditioning, refrigeration, and heat pump systems. In this question, we want to see how well this fluid can be modelled using the ideal gas law. To determine this, complete the following: a) Determine the compressibility of R-134a at 1.6 MPa and 70 C using: i. only data from tables in the Equations and Data Booklet. ii. the compressibility chart on page 22 of the Equations and Data Booklet (plus any data you need from tables to use this chart). b) Can the density of R-134a be calculated using the ideal gas law within 5% accuracy? c) Determine the change in specific enthalpy for R-134a at 1.6 MPa when the temperature changes from 70C to 100 C when: i. assuming that R-134a is an ideal gas with a constant heat capacity of 0.8367 kJ/kg.K (which is the ideal gas heat capacity at 300 K). ii. using the property tables. d) What are two reasons for the difference in answers between (i) and (ii) for part (c)Step by Step Solution
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