I still have proplem with the second function when i ever i try test case 2 i get wrong output this is the code

void NestedStatements(string S1, string S2, int& count) { count = 0; size_t pos = 0; while ((pos = S2.find(S1, pos)) != string::npos) { count++; pos += S1.length(); }

HW5: Function Overloading You are required to write two overloaded functions called NestedStatements that take in the following formal parameters list: - Function 1: takes as input two strings (i.e. S1 and S2 ) and returns true if the string S1 appears in the string S2 at least once. Otherwise, the function returns false. For example, if S1 = "eat" and S2 = "the weather is nice" then the function returns TRUE. Similarly, if S1 = "zoo" and S2 = "the zoo is closed" then the function also returns TRUE. - Function 2: takes as input two strings (i.e. S1 and S2) and an integer reference variable count, and saves the number of times the string S1 appears in the string S2 in the variable count. For example, if S1= "the" and S2= "the weather is nice" then the value of count at the end of the function is 2. Similarly, if S1 = "cloned" and S2= "the zoo is closed" then the value of count at the end of the function is 0. Do not write and submit the main subroutine, or any include statments, these are already written and hidden from you. However, if you want to test your solution in any IDE (e.g., CodeBlocks, CLion, onlinegdb.com), then you will need to write your own main there for testing purposes. IMPORTANT NOTES - Do not change the given functions headers. - Do not add any cout statements inside the functions. - Assume all the alphabetical characters in S1 and S2 are lowercase. Sample Testcase 2 (not graded, for student use only): Input: Suppose main calls NestedStatements as NestedStatements("ear", "heart, tears, ear, and earn", v1) Function Output: The value of v1 in the main after the call should be 4 The function does not print anything, only stores the value 4 in v1