I think .now it is 6/60=.10 and 30/60=.50- then 50560x.10=5056 machine hours. 5056 machine hours x 5.00 per shirt for 25280 for swoop units. 7000 machine hours- 5056= 1944 remaining for rufus. Thus 1944 machine hours x 15.00 a shirt for 29160 , total optimal ix 55440?

Determining the optimal Product Mix with One Constrained Resource and a Sales Constraint Comfy Fit Company manufactures two types of university sweatshirts, the Swoop and the Rufus, with unit contribution margins of $5 and $15, respectively. Regardless of type, each sweatshirt must be fed through a stitching machine to affix the appropriate university logo. The firm leases seven machines that each provides 1,000 hours of machine time per year. Each Swoop sweatshirt requires 6 minutes of machine time, and each Rufus sweatshirt requires 30 minutes of machine time. Assume that a maximum of 50,560 units of each sweatshirt can be sold. Required: If required, round your answers to the nearest whole number. 1. What is the contribution margin per hour of machine time for each type of sweatshirt? Contribution Margin 50 Rufus 30 Swoop 2. What is the optimal mix of sweatshirt? Optimal Mix Swoop 10,000 x units o x units 3. What is the total contribution margin earned for the optimal mix? 50,000 Rufus