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I think the first part is corect but how do I find Kc? 2. (10 pts) At 425 C, K, -4.18x 10 for the reaction

I think the first part is corect but how do I find Kc?

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2. (10 pts) At 425 C, K, -4.18x 10" for the reaction 2_HBrg) 1_11268) H2(g) + ? Br2(8) In one experiment, 0.2 atm of HBr, 0,01 atm of H, and 0.01 atm of Br, are introduced into the container, Is the reaction at equilibrium? If not, in which direction will it proceed? .01.01 = .0025 LEFT Calculate K. 425 + 273=698K -9 4.18x10 =

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