I To illustrate that the length of a smooth space curve does not depend on the parameterization used to compute it, calculate the length of one tum of the helix with the following parameterizations. ill a. r(t) = (cos 4t)i + (sin 4t)j + 4tk, 0 S t s E b. r(t)=|:cos [HH [sin [ghgh 05t54n c. r(t) = (cos t)i (sin t)j tk, 221515 0 Note that the helix shown to the right isjust one example of such a helix, and does not exactly correspond to the parametrizations in parts a, b, or c. a. L = (Type an exact answer, using 1: as needed.) b. L: (Type an exact answer, using 1: as needed.) c. L = (Type an exact answer, using 1: as needed.) \fDetermine the maximum curvature for the graph of f(x) = 3 In (5x). The maximum curvature is at X =