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I used the command ping l 300 134.71.177.148 and then captured some frames with Wireshark. (a) Some of my frames look like this: Which shows

I used the command "ping l 300 134.71.177.148" and then captured some frames with Wireshark.

(a) Some of my frames look like this: image text in transcribedWhich shows a length of 342 bytes of ping l 300 and also in the middle panel and bottom panel, you can see image text in transcribed

Here 0x148 in bytes 16 and 17 is equal to decimal 256 + 4*16 + 8 = 328.

So you see that with ping l 300, you get 328 decimal (=0x0148) in IP header, but 342 bytes as interpreted by Wireshark. Why 300 appears as 328 in IP header and 342 in the frame line (top panel) and also middle panel? Explain!

(b)Based on this, deduce the minimum ICMP frame length that you can see in Wireshark. What will be in bytes 16 and 17 or IP total length field?

(c) Can you run ping l 70000 134.71.177.148? Why?

(d) Now run ping l 3000 134.71.177.148 (number after l is 3,000, or three thousands). What do you see in Wireshark. Based on the same reasoning as in Q1, do you expect total length to be 3,028 in decimal and Wireshark says the length is 3,042? If not, why? Explain.

(e) Is it possible to have IP frame with 3 or more fragments? If so, what ping command would you use? (hint: use ping l 134.71.177.148, where is a number picked by you). Fragmentation is explained in the following slide: image text in transcribed

136 192.168.1.18 2 134.71.177 14B 28 12.263477 134.71.177.148 192.168.1.10 342 Echo (ping) request id-0x32B1, seq 41/1B4g6, tt 1-12B reply in 28) CMP ICMP 342 Echo (ping) reply id 0x0001. seq 41/10496, ttl 240 (request in 27

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